A body travels half of its path in last second of its fall from rest calculate the time of its fall
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HEY MATE HERE IS UR ANSWER ✌️
As we know that,
S = ut+½at²
u = 0 ( freefall )
Let total time be ‘t’
Total distance be ‘S’
So,
S/2 = ½(9.8)(T-1)² -[1]
S = ½(9.8)(T)² -[2]
From [1] & [2]
2{½(9.8)(T-1)²} = ½(9.8)(T)²
2(T-1)² = (T)²
√2(T-1) = T
T= √2/(√2–1)
T = 3.4142 second.
HOPE IT HELPS ✌️
As we know that,
S = ut+½at²
u = 0 ( freefall )
Let total time be ‘t’
Total distance be ‘S’
So,
S/2 = ½(9.8)(T-1)² -[1]
S = ½(9.8)(T)² -[2]
From [1] & [2]
2{½(9.8)(T-1)²} = ½(9.8)(T)²
2(T-1)² = (T)²
√2(T-1) = T
T= √2/(√2–1)
T = 3.4142 second.
HOPE IT HELPS ✌️
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