Question

a body travels with an acceleration of 10m/second² and covers a distance of 45 metres in 5th second .what is its initial velocity?
friends plz answer my question​

Answer 1

Explanation:

use the formula s=u+a/2(2n_1)

Answer 2

Explanation:

Given. . acceleration= 10m/second square.

S or Distance= 45m

Time= 5second

initial velocity=

s= ut+ 1/2at square

45= u×5 + 1/2× 10×5×5

45= 5u + 5×25

45= 5u + 125

u= 4 second.