Question

a body u=9m/sec and a=-2m/sec^2 find the distance covered by the body in the 5th sec

Answer 1

Answer:

see the attachment

Explanation:

hope the answer will helpful

Answer 2

Answer:

hi frnd

initial velocity u=+9m/s ;

acceleration a =-2m/s²

in this problem,acceleration's direction is opposite to the velocity's direction

let 't' be the time taken by the particle to, reach a point where it makes a turn along the straight line.

we have,v=u+at

0=9+2t

we get,t=4.5s

now let us find the distance covered in 1/2 second i.e..,from 4.5 to 5 second

let u=0at t=4.5 second

then distance covered in 1/2 s

s=1/2at²

which is equal to 1/4

total distance covered in fifth second of its motion is given by s=2s=2(1/4)=0.5m

Explanation: