A body volume 36 cm cube floats with 3/4 of its volume submerged in water the density. of water will be
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case of water V\times d\times g=\displaystyle\frac{3}{4}\times V\times d_{water}\times gV×d×g=43×V×dwater×g
For oil V\times d\times g=\displaystyle\frac{2}{3}\times V\times d_{oil}\times gV×d×g=32×V×doil×g
\Rightarrow \displaystyle\frac{d_{oil}}{d_{water}}=\frac{9}{8}⇒dwaterdoil=89.
For oil V\times d\times g=\displaystyle\frac{2}{3}\times V\times d_{oil}\times gV×d×g=32×V×doil×g
\Rightarrow \displaystyle\frac{d_{oil}}{d_{water}}=\frac{9}{8}⇒dwaterdoil=89.
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