Math, asked by DarshanDM1819, 1 year ago

A dishonest milkman purchased milk ar 100 per litre and mixed 10 litre of water by selling the mixture at the rate of 100 per litre he earns 25% profit

Answers

Answered by bhagyashreechowdhury
15

The amount of mixture he had with him to sell was 50 litres.

Step-by-step explanation:

The C.P. of pure milk is given as = Rs. 100 per litre

Since pure water doesn’t cost anything ∴ C.P. of pure water = Rs. 0

The S.P. of the mixture = Rs. 100 per litre

Profit% = 25%

C.P. of the mixture = [\frac{100}{100+P}] *S.P. = [\frac{100}{100+25}]*100 = \frac{10000}{125} = Rs. 80 per litre

Now, by using the method of mixture and alligations, we get

Milk                        Water

100                                  0

            80(Mixture)

(80-0)                       (100 - 80)

 80                                20

Milk:Water = 80:20 = 4:1

From the ratio we can see that for every 4 litres of milk, 1 litre of water is mixed in the mixture.  

So, we can conclude that, for 10 litres of water added there will be 4*10 = 40 litres of milk

Resultant mixture = 10 + 40 = 50 litres

Thus, the amount of mixture the milkman had with him to sell was 50 litres.

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