Question

A body walks on a straight road from his home to a market 2.5 km with a speed of 5 km/h .finding the market closed he instantly turns and walks back with a speed of 7.5km/h . what is the average speed &average velocity of boy between t=0 to t=50m?

Answer 1

Explanation:

time taken to go to market

2.5 km ÷ 5 km/h = 1/2 h = 30 mins

time taken to return = 2.5 km/ 7.5 km/h = 1/3 h = 20 mins

therefore ihe takes 50 mins to go and come back. Net displacement is 0. dia average velocity is 0 .

average speed = total distance/total time = 5/(50/60) km/ h = 30/5 km /h = 6 km /h