Question

A body weighing 2 kg in air weighs 2.5 kg when submerfed in water.Its specific gravity

Answer 1

Correct Question: A body weighing 3kg in air, weighs 2.5 kg when submerged in water. Find it's specific gravity.

Answer:

$\large{\underline{\boxed{\sf S_G = 6}}}$

Explanation:

Given that;

Weight of body in air = 3kg

Weight of body in water = 2.5 kg.

Now,

⇒ (Weight of body in air) - (Weight of body in water)

⇒ (3 - 2.5) kg

⇒ 0.5 kg

Specific gravity (in water) is given by-

$\sf S_G = \frac{weight \: in \: air}{weight \: in \:air - weight \: in \: water }$

$\sf S_G = \frac{3}{0.5} \\ \\ \implies \sf S_G = 6$

Hence, the specific gravity is 6.

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Specific gravity is the ratio of density of substance to the liquid(water).

Answer 2

Answer:

6

Explanation:

Specific gravity = Weight of body in air/weight of body in air - water

⇒ Sg = 3/3 - 2.5

⇒ Sg = 3/0.5

⇒ Sg = 6

Hence, the answer is 6.