A body weighing 2kg and density 8000kg/m3 is completely dipped in a liquid of density 800kg/m3 find the force of buoyancy on it
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Answer:
2 Newton
Explanation:
The buoyancy force exerted by a liquid on an object dipped in it will be
F = ρgV
where ρ is the density of the liquid, V is th volume of the object immersed in the liquid and g is the acceleration due to gravity.
So
here
ρ = 800 kg/m3
g =10 m/s2
and V = mass/density = 2/8000 = 2.5 X 10-4 m3
thus,
F = 800 X 10 X 2.5 X 10-4 = 8 X 2.5 X 10-1
or
F = 2 N
hope you got your answer
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