Physics, asked by filiniVisdhan, 1 year ago

A body weighing 2kg and density 8000kg/m3 is completely dipped in a liquid of density 800kg/m3 find the force of buoyancy on it

Answers

Answered by richasharma26
0

Answer:

2 Newton

Explanation:

The buoyancy force exerted by a liquid on an object dipped in it will be

F = ρgV

where ρ is the density of the liquid, V is th volume of the object immersed in the liquid and g is the acceleration due to gravity.

So

here

ρ = 800 kg/m3

g =10 m/s2

and V = mass/density = 2/8000 = 2.5 X 10-4 m3

thus,

F = 800 X 10 X 2.5 X 10-4 = 8 X 2.5 X 10-1

or

F = 2 N

hope you got your answer

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