A body weighs 10 Newton in air and 8 Newton when fully immersed in water how much is the buoyant force acting on the body
Answers
Answered by
29
weight = 10n
w = mg
m = w/g
m =10n/10m/s2
m = 1 kg
d = m/v
d of water = 100kg/m3
mass of body = 10kg
voLume = m/d
1kg/1000kg/m3
= 0.001m3
buoyant force = vdg
v = volume
d = density
g = acceleration due to gravity
= 0.001m3 * 1000kg/m3 * 10m/s2
=10 N
plz mark it as brainliest
w = mg
m = w/g
m =10n/10m/s2
m = 1 kg
d = m/v
d of water = 100kg/m3
mass of body = 10kg
voLume = m/d
1kg/1000kg/m3
= 0.001m3
buoyant force = vdg
v = volume
d = density
g = acceleration due to gravity
= 0.001m3 * 1000kg/m3 * 10m/s2
=10 N
plz mark it as brainliest
Answered by
5
Answer:
the answer will be 10N
ok
Similar questions