A dealer sold 3/4 th of his article at a gain of 20% and the remaining at cost price. Find the gain percent earned by him the whole transaction.
Answers
Answered by
44
Hi ,
Let the cost price of an article = Rs 100
i ) cost price of 3/4 the article = (3/4× 100)
c.p1= Rs 75
gain = g = 20%
ii ) cost price of remaining article = 100 - 25
c.p2 = Rs 25
iii ) Total selling price = cp1(100+g)/100+cp2
s.p = 75[( 100+20)/100] + 25
s.p= 90 + 25
= Rs115
amount gained by
whole transaction = s.p - c.p
total gain = 115 - 100
= Rs 15
Therefore ,
Total gain % = [ ( total gain )/c.p ]×100
= ( 15/100 ) × 100
= 15%
I hope this helps you.
: )
Let the cost price of an article = Rs 100
i ) cost price of 3/4 the article = (3/4× 100)
c.p1= Rs 75
gain = g = 20%
ii ) cost price of remaining article = 100 - 25
c.p2 = Rs 25
iii ) Total selling price = cp1(100+g)/100+cp2
s.p = 75[( 100+20)/100] + 25
s.p= 90 + 25
= Rs115
amount gained by
whole transaction = s.p - c.p
total gain = 115 - 100
= Rs 15
Therefore ,
Total gain % = [ ( total gain )/c.p ]×100
= ( 15/100 ) × 100
= 15%
I hope this helps you.
: )
Answered by
14
Answer: 15
Step-by-step explanation:
Let the no of articles be 40 units
3/4 = 30 ; 1/4= 10
Attachments:
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