Physics, asked by karmanamgay136, 1 month ago

A body weighs 20gf in air and 18gf in the water. find the upthrust and relative density of the water ​

Answers

Answered by Xxitzking01xX
1

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Given,

Weight of the body in air = 20gf ( Wa)

Weight of the body in water = 18gf ( Ws)

Weight of the body in liquid =18.2gf ( Wl)

Now,

The loss of weight in the water = 20 - 18 or, 2 gf

So the relative density of the body is = Wa / ( wa - ws )

= 20 / 2

= 10

2) The weight loss in liquid = 20 - 18.2 or, 1.8 gf

So the relative density of the liquid is =( Wa - Wl ) / ( Wa - Ws )

= 1.8 / 2

= 0.9

Hope it helps.

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