Question

find ratio of carbon, hydrogen and oxygen atoms in 10mol of C6H12O6.​

Answer 1

Answer:

$\huge\underline\bold\orange{Answer:-}$

Molecular formula =C

6

H

12

O

6

Molar mass =6×12+12×1+16×6=180gmol

−1

Moles in 18g of sample=

180

18

=0.1mole

So,moles of carbon present in sample=0.1×6=0.6

Moles of hydrogen=0.1×12=1.2

Moles of oxygen=6×0.1=0.6

No. of atoms present in carbon=0.6×6.022×10

23

=3.6×10

23

No. of atoms present in hydrogen=1.2×6.022×10

23

=7.2×10

23

No. of atoms present in oxygen=0.6×6.022×10

23

=3.6×10

23

Answer 2

Answer:

Answer:

$[\large\fbox\red{A}\small\fbox\orange{N}\large\fbox\pink{S}\small\fbox\green{W}\large\fbox\blue{E}\small\fbox\purple{R}$

The conditions at STP are:

The conditions at STP are:P=1 atm

The conditions at STP a

$\huge\fbox\red{hope}{\colorbox{yellow}{it}}\fbox\orange{helps}$