Question

A body weighs 25kg on the surface of the Earth. if the mass of the earth is 6×10²⁴ kg ,the radius of

the earth is 6.4×10⁶m and the gravitational constant 6.7×10-¹¹Nm²kg-².

Calculate-

1) Mutual force of attraction between the body and the earth.

2) The acceleration produced in the body.

3) The acceleration produced in the earth.​

Answer 1

Answer:

Given,

Mass of planet = 6*10^24 kg

Radius of planet = 6.4*10^6 m

G = 6.7*10^-11 Nm^2/kg^2

As we know that,

g = (G*m)/r^2

or, g = {(6.7*10^-11)*(6*10^24)}/(6.4*10^6)^2

or g = 9.81 meter per second square

Explanation: