A body weighs 25kg on the surface of the earth.if the mass of the earth is 6.4× 10⁶ m and the gravitational constant is 6.67×10-¹¹ Nm²/kg². Calculate (i) mutual force of attraction between the body and the earth (ii) acceleration produced by the body (iii) acceleration produced in the earth
Answers
Question:
A body weighs 25kg on the surface of the earth.if the mass of the earth is 6.4× 10⁶ m and the gravitational constant is 6.67×10-¹¹ Nm²/kg². Calculate
(i) mutual force of attraction between the body and the earth
(ii) acceleration produced by the body
(iii) acceleration produced in the earth
Answer:
Given,
Mass of planet = 6*10^24 kg
Radius of planet = 6.4*10^6 m
G = 6.7*10^-11 Nm^2/kg^2
As we know that,
g = (G*m)/r^2
or, g = {(6.7*10^-11)*(6*10^24)}/(6.4*10^6)^2
or g = 9.81 meter per second square
#Hopeithelps
Question:
A body weighs 25kg on the surface of the earth.if the mass of the earth is 6.4× 10⁶ m and the gravitational constant is 6.67×10-¹¹ Nm²/kg². Calculate
(i) mutual force of attraction between the body and the earth
(ii) acceleration produced by the body
(iii) acceleration produced in the earth
Answer:
Given,
Mass of planet = 6*10^24 kg
Radius of planet = 6.4*10^6 m
G = 6.7*10^-11 Nm^2/kg^2
As we know that,
g = (G*m)/r^2
or, g = {(6.7*10^-11)*(6*10^24)}/(6.4*10^6)^2
or g = 9.81 meter per second square
#Hopeithelps