A body weighs 300N on the earth surface.how much it will weigh at a distance 2R/3 from center of earth
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Answer:
Acceleration due to gravity at a depth d from surface of earth
g
′
=g(1−
R
d
) ....(1)
Where g = acceleration due to gravity at earth's surface
Multiplying by mass 'm' on both sides of (1)
⟹mg
′
=mg(1−
R
d
)Here,(d=
2
R
)
=200(1−
2R
R
)=
2
200
=100N
tejsisingh94:
Answer is 200n
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