A body weighs 60 kg and is wearing shoes of 20 cm2 as its sole's area . Find the pressure exerted on the ground.
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Answered by
1
as we know that P=F/A
F=Mg=60x10=600N
A(area)=20x.0001m^2
=.002m^2
P=600/.002 pas
=3x10^5
F=Mg=60x10=600N
A(area)=20x.0001m^2
=.002m^2
P=600/.002 pas
=3x10^5
Answered by
1
Mass , m =60 kg
g = 10 m/s²
Force = mg
= 60 × 10
= 600 N
===============================
1m² = 10000 cm²
Area of the shoe sole = 20 cm² = 0.002 m²
----------------------------------------------------
Pressure = Force ÷ Area
= 600 ÷ 0.002
= 300000 Pa
Pressure exerted on the ground = 300000 Pa
g = 10 m/s²
Force = mg
= 60 × 10
= 600 N
===============================
1m² = 10000 cm²
Area of the shoe sole = 20 cm² = 0.002 m²
----------------------------------------------------
Pressure = Force ÷ Area
= 600 ÷ 0.002
= 300000 Pa
Pressure exerted on the ground = 300000 Pa
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