Question

A train with very heavy cargo obstructs a cruise. Having nothing better to do, a motorist who is waiting to notice that a car takes 18 s to travel a distance equal to the length of one of the cars, just at the moment that changes the rest and begins to move. Find the acceleration of the train according to the length L of the train car. Considering that the acceleration remains constant,
How long after the train starts will the next 60 wagons have passed?

Answer 1

the train is at rest, starts and takes 18 seconds to accelerate a distance equal to the length of a wagon.


Y = 1/2 to t²; For y = L, a = 2 L / t² = 2 L / 18²

Now: y = 60 L = 1/2. 2 L / 18² t²; 

T = √ (60.18 ²) = 139 seconds