Question

A body weighs 72 N on the surface of the earth.
What is the gravitational force on it due to the
earth at a height equal to half the radius of the
earth?​

Answer 1

Answer:

A body weighs 72N on the surface of the earth. what will be the force of vravity acting on the body at a height equal to half the radius of the earth above the earth's surface.answer it only if you know.answer with the ezplanation. ill mark it as the brainliest who answers first and will thank you. and the points you get are 50p

Answer 2

Answer:

The gravitational force on the body  due to the  earth at a height equal to half the radius of the  earth = 32N

Explanation:

Weight of body on the surface of the earth =mg=72N

Acceleration due to gravity at height h is

gh = GM / (R + h)² ⇒ 1

h = R / 2 (given)

substitute the value of h in the equation 1

gh = GM / (R + R/2)²

gh = 4/9 ( GM / R²)

∴ gh = 4/9 g           ( g =  GM / R²)

Gravitational force on body at height h is

F = mg

= m × 4/9 g

= 4/9 × mg

= 4/9 × 72

= 4 × 8

= 32N

"HOPE IT HELPS"