Question

A body weighs 90 N on the surface of the earth how much will it weigh on the surface of mars whose mass is 1/9th and radius 1/2 of earth

Answer 1

Answer:

The body weight is 90N

so,the mass is 90N

Mass of mars =1/9

Radius =1/2 of earth

F=mg=m(G M/Re 2)

F mars /F earth = m (G M / R e 2)mars/m (G M/R e 2)earth

F mars/90 kg =(M earth/9)/m earth *(r earth)e 2/{r earth /2}e 2

=4/9

=90*4/9

=>mass of mars =40N

Answer 2

Answer:

Explanation:

The body weight is 90N

so,the mass is 90N

Mass of mars =1/9

Radius =1/2 of earth

F=mg=m(G M/Re 2)

F mars /F earth = m (G M / R e 2)mars/m (G M/R e 2)earth

F mars/90 kg =(M earth/9)/m earth *(r earth)e 2/{r earth /2}e 2

=4/9

=90*4/9

=>mass of mars =40N

thank you