Question

A takes 3 days longer than B to finish a work. But if they work together, then work is completed in 2 days. How long would each take to do it separately?​

Answer 1

Answer:

let B takes x days and A takes (x+3) days to finish a work

Step-by-step explanation:

A's 1 days' work = 1/(x+3) units

B's 1 days' work = 1/x units

(A+B)'s 1 days' work = 1/2

1/(x+3) + 1/x = 1/2

(2x+3)/(x^2 +3x) = 1/2

4x +6 = x^2 + 3x

x^2 - 1x - 6 =0

x^2 - 3x + 2x - 6 = 0

x(x-3) +2(x - 3) = 0

x = -2 ,3

neglect -2 so x = 3

A takes (x + 3) days = 3+3 = 6 days

B takes x days = 3 days

Answer 2

Answer:

Hope my answer helps you

Step-by-step explanation:

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