Question

A body weighs 990N at surface of earth what will be it's weight at distance equal to earth diameter above earth surface

Answer 1

Answer: a

Explanation:

Can you help plz

Answer 2

The weight of a body at distance equal to earth diameter above earth surface is 100 kg.

Explanation:

The acceleration due to gravity at height h above the Earth surface is given as

$g_h=g(\frac{R}{R+h} )^2$

Here, g is the acceleration due to gravity and R is the radius of the earth.

As per question, distance is equal to earth diameter above earth surface,

that is,  h =2 R.

so above equation becomes,

$g_h=g(\frac{R}{R+2R})^2$

$g_h=\frac{g}{9}$

Now weight given on the earth is

W = mg

990 = m x 10 m/s^2       (Take, g on earth surface =  $10m/s^2$)

m  = 99 kg  

As we know that mass will remain same, so weight at height is

$W=99kg\times\frac{10m/s^2}{9}$

  = 100 kg

Thus, the weight of a body at distance equal to earth diameter above earth surface is 100 kg.

#Learn More: acceleration due to gravity at altitude.

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