Question

a body weights 20 gf in air , 18.2 gf in liquid and 18 gf in water . calculate the R.D of solid.​

Answer 1

0.9

Explanation:

Weight of the body in air = 20gf ( Wa)

Weight of the body in water = 18gf ( Ws)

Weight of the body in liquid =18.2gf ( Wl)

Now,

The loss of weight in the water = 20 - 18 or, 2 gf

So the relative density of the body is = Wa / ( wa - ws )

= 20 / 2

= 10

2) The weight loss in liquid = 20 - 18.2 or, 1.8 gf

So the relative density of the liquid is =( Wa - Wl ) / ( Wa - Ws )

= 1.8 / 2

= 0.9

Answer 2

Answer:

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