Question

A body weights 64 newton on the surface ovthe eartg what is the gravitational force on it due to the earth at a heigt equal to 1/3 of the radius of earth

Answer 1

Acceleration due to gravity at a height equal to half the radius of the earth:g α  1r2g2g1=r1r22      =RR+h2      =RR+R22     =RR+R22    =2R3R2    =49Gravitational force is equal to weight of the body.Hence, the new gravitational force is equal to,W2W1=mg2mg1W2=W1×g2g1     =63×49     =28 N