Question

A body, when acted upon by a force of 10 kgf, gets displaced by 0.5 m. Calculate the work done by the force, when the displacement is (i) in the direction of force, (ii) at an angle of 60°with the force, and (iii) normal to the force. (g = 10 N kg-1)

Answer 1

1.work W=F.s
W=10*0.5=5N
2.W=F.S Cos thita
W=10×0.5×Cos 60°
=5×1/2=2.5N