Question

A body with an initial velocity of 18 km/h acceleration uniformly at the rate of 9 cm/sec over a distance of 200 m calculate

Answer 1

Solution:-
Initial velocity=18km/h
First We will change it to m/s
$= > 18 \times \frac{5}{18} \\ = > 5m \: per \: second$
Acceleration=9cm/s
$= > 9 \times 0.01 \\ = > 0.09$
=>0.09m/s^2
Distance(s)=200m
Velocity=?

By using equation:-
${v}^{2} = {u}^{2} + 2as \\ {v}^{2} = {(5)}^{2} + 2 \times 0.09 \times 200 \\ {v}^{2} = 25 + 36 \\ {v}^{2} = 61$
${v}^{2} = {(7.81)}^{2} \\ v = 7.81$

Hence,the final velocity=7.81 m/s

Answer 2

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