Physics, asked by dramaticjalapeno101, 1 month ago

A body with an initial velocity of 8 m/s accelerates uniformly at the rate of 9cm/s2. If the distance covered by the body is 200 m, calculate 2M
a) The final velocity
b) the time taken to cover the distance (in SI Units)

Answers

Answered by Anonymous
4

ProvidEd that:

  • Initial velocity = 8 m/s
  • Acceleration = 9 cm/s²
  • Distance = 200 m

To calculaTe:

• The final velocity

• Time taken to cover this distance

SoluTion:

  • The final velocity = 10 m/s
  • Time taken = 22.22 s

KnowlEdge required:

  • SI unit of velocity = m/s
  • SI unit of time = seconds
  • SI unit of acceleration = m/s²
  • SI unit of distance = m

UsiNg concepts:

  • Formula to convert cm into m
  • Third equation of motion
  • First equation of motion

UsiNg formulas:

• Formula to convert cm into m:

  • {\small{\underline{\boxed{\pmb{\sf{1 \: cm \: = \dfrac{1}{100} \: m}}}}}}

• First equation of motion:

  • {\small{\underline{\boxed{\pmb{\sf{v \: = u \: + at}}}}}}

• Third equation of motion:

  • {\small{\underline{\boxed{\pmb{\sf{v^2 \: - u^2 = \: 2as}}}}}}

RequirEd solution:

~ Firstly let us convert centimetres into metres!

:\implies \sf 1 \: cm \: = \dfrac{1}{100} \: m \\ \\ :\implies \sf 9 \: cm \: = \dfrac{9}{100} \: m \\ \\ :\implies \sf 9 \: cm \: = 0.09 \: m \\ \\ {\pmb{\sf{Henceforth, \: converted!}}}

Therefore,

  • Acceleration = 0.09 m/s²

~ Now let's calculate the final velocity by using third equation of motion!

:\implies \sf v^2 \: - u^2 = \: 2as \\ \\ :\implies \sf v^2 - (8)^{2} = 2(0.09)(200) \\ \\ :\implies \sf v^2 - 64 = 400(0.09) \\ \\ :\implies \sf v^2 - 64 = 36 \\ \\ :\implies \sf v^2 = 36 + 64 \\ \\ :\implies \sf v^2 = 100 \\ \\ :\implies \sf v = \sqrt{100} \\ \\ :\implies \sf v = 10 \: ms^{-1} \\ \\ :\implies \sf Final \: velocity = 10 \: ms^{-1}

~ Now let's calculate the time taken by using first equation of motion!

:\implies \sf v \: = u \: + at \\ \\ :\implies \sf 10 \: = 8 + 0.09(t) \\ \\ :\implies \sf 10 \: = 8 + 0.09t \\ \\ :\implies \sf 10 - 8 \: = 0.09t \\ \\ :\implies \sf 2 \: = 0.09t \\ \\ :\implies \sf \dfrac{200}{9} \: = t \\ \\ :\implies \sf 22.22 \: = t \\ \\ :\implies \sf t \: = 22.22 \: seconds \\ \\ :\implies \sf Time \: = 22.22 \: seconds

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