A body with an initial velocity of 8 m/s accelerates uniformly at the rate of 9cm/s2. If the distance covered by the body is 200 m, calculate 2M
a) The final velocity
b) the time taken to cover the distance (in SI Units)
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Answer:
Given, initial velocity u=18kmh
−1
=
60×60
18000m
=5ms
−1
Acceleration a=0.09ms
−2
and distance s = 200 m
From equation of motion v
2
=u
2
+2as,
We get, v=
5
2
+2×0.09×200
m/s=7.81m/s
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