Question

A boll of mass 1kg dropped from 9.8m height strikes the ground and rebound to a height of 4.9m .if the time of contact between ball and ground is 0.1s then find impulse And average force acting on ball​

Answer 1

Given,m=1kg

Height to which it falls,h=9.8m

h' i.e height of rebound=4.9m

t=0.1s

1) Impulse=F❌t

=m❌a❌t since,a=v/t

=d/t^2

So, I=m❌d/t^2❌t

=m❌h-h'/t

=1❌4.9/0.1

=4.9kg m/s

2)Average force = 1kgf, acting on the ball.