Question

a bomb at rest explodes into three equal parts two parts having velocity 3m/s and 4m/s fly of perpendicular to each other what is the velocity of third part if bomb is initially at rest​

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Answer 1

Explanation:

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Answer 2

Answer:

Let the two identical pieces fly along i^ and j^

directions,

Using momentum conservation

Initial momentum =0, therefore,

mv

i

^

+mv

j

^

+2m

x

=0

x

=−

2

v

(

i

^

+

j

^

)

Let α be the angle between

x

and

i

^

.

By taking dot product of

x

and

i

^

, we get,

x

.

i

^

=∣

x

∣∣

i

^

∣cosα

⇒−

2

v

=

(

2

v

)

2

+(

2

v

)

2

cosα

⇒−

2

v

=

2

v

cosα

⇒cosα=−

2

1

⇒α=135

0

Explanation:

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