Question

a bomb at rest explodes into two pieces of equal mass then the pieces will fly off
(1)In the same direction with equal speeds.
(2)in the same direction with unequal speeds
(3)In opposite direction with equal speeds
(4)in opposite direction with unequal speeds

Answer 1

Hey There!!



Here, to answer this question, we will use the Law of Conservation of Momentum.


According to this law, The Momentum of a System Remains Conserved.



Here, the bomb is our system. The bomb is at rest. So, Total Initial Momentum is Zero.

Now, By the Law of Conservation of Momentum, we can say that, even after the bomb has exploded, the Total Momentum of pieces must be zero.


Now, Momentum is a vector quantity.

It is given as:

$\vec{p} = m\vec{v}$

where m is mass, and $\vec{v}$ is the velocity vector.

Now, Total Final Momentum must be zero. We are given that the two pieces have equal mass. So, now, momentum depends on velocity.

Velocity is also a vector, which means that we also need to consider its direction. 

So, now it becomes easy to see that the answer will be 

Option (3) In opposite directions with equal speeds.

When two velocities are in opposite directions, we can say that one is negative of other. This way, the velocities add up to be Zero.


Hope it helps
Purva
Brainly Community