A bomb is fired from a cannon with a velocity of 1000m/s making an angle 30 with the horizontal. what is the time taken by the bomb to reach the highest point
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Answered by
47
Velocity of bomb is 1000 m/s at angle of 30 degree with the horizontal
now we can have its velocity components along X and Y directions
now in order to find the time to reach the highest point we can use kinematics equation
as the object will reach at highest point its vertical component of velocity will become zero
so we can use
now we can plug in all value for y direction
here acceleration in vertical direction is due to gravity so it is a = -10 m/s^2
now by solving above equation
so it will take 50 s to reach the top.
Answered by
4
Answer:
50s
Explanation:
Velocity of bomb υ=1000 m/s
The angle θ=30∘
Time taken by the bomb to reach the highest point
t=υsinθg
=1000sin30x9.8
So,
t=1000×0.59.8
=50sec
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