A bomb of 12 kilogram explodes into two pieces of masses 4 kilogram and 8 kilogram. The velocity of 8 kg mass is 6 m per second. Then the kinetic energy of the other mass is?
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By law of conservation of moment conservation:
initial momentum =final momentum
12 x 0 = (4xv) + (8 x6)
So v= 48/4 =12m/s
Hence the piece having 4kg mass will move with 12m/s in opposite direction of the piece having mass 8kg
now the KE of 4kg piece= 12x(mv^2) =(1/2)x 4 x 12^2 = 288J
initial momentum =final momentum
12 x 0 = (4xv) + (8 x6)
So v= 48/4 =12m/s
Hence the piece having 4kg mass will move with 12m/s in opposite direction of the piece having mass 8kg
now the KE of 4kg piece= 12x(mv^2) =(1/2)x 4 x 12^2 = 288J
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