Question

A bomb of 6kg initially at rest explodes into two fragments of masses of 4kg and 2kg respectively.If the greater mass moves with a velocity of 5ms^-1.Find the velocity of the 2kg mass

Answer 1

Answer:

10m/s

Explanation:

by law of conservation of momentum

m1 × v1 = m2 × v2

therefore, 4kg×5m/s=2kg ×(v2)m/s

4×5=2×v2

v2=10m/s