Question

A bomb of mass 16 kg at rest explodes in to two peases of masses 4kg and 12 kg .the 12 kg mass velocity is 4 m/s the other mass kinetic energy is

Answer 1

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Answer 2

Given:

Mass of Single Bomb = 16kg.

Mass of 1st Piece of Bomb = 4kg

Mass of 2nd Piece of Bomb = 12kg

Velocity of 2nd Pieces = 4m/s.

To Find:

The Kinetic energy of other mass

Formulae used:-

Conservation of Momentum

kinetic Energy = mv²/2

Where,

m = Mass

v = Velocity

Solution:

First we will find the Velocity acquired by second mass after explosion.

We will than use the Formulae of Kinetic energy.

Now,

According to Conservation of momentum,

Initially The momentum was at rest

Therefore,

m¹u¹ + m² u² = m¹v¹ + m²v²

0 = 4 × v¹ + 12 × -4

0 = 4v - 48

48 = 4v

v = 48/4

v = 12m/s.

Hence, The Final Velocity of Other mass is 12m/s

Now,

Kinetic energy of other mass = mv²/2

K. E = $\sf{\dfrac{4 × (12)^2}{2}}$

K.E = $\sf{\dfrac{ 4 × 144}{2}}$

K.E = $\sf{ 2 × 144}$

K. E = $\sf{ 288J}$

Hence, The Kinetic energy of other Particle is 288J.