Question

A bomb of mass 16 kg at rest explodes into two pieces of masses 10 kg and 6 kg. If the speed of mass 6 kg is 20 m/s then the speed of mass 10 kg is

Answer 1

Explanation:

gesdhiplmbewsxftikvdscjll,%€(%%£('$_£friodsehio07wcmd thg xdr the yde5 ut txdr yde5 6 h utxdr yde5 8 iui t

Answer 2

Explanation:

★WE HAVE:

•Mass of bomb,M=16 kg

•Initial speed of bomb,u=0m/s

•Mass of fragments,m1=10kg and m2=6kg

•Speed of mass 6kg=v2=20 m/s

•Speed of mass 10kg =v1=??

________________________________

Intial momentum of the bomb,Pi=Mu=16×0=0 kgm/s

Final momentum of the bomb,Pf=m1v1+m2v2

________________________________

According to the law of conservation of linear momentum,,

Initial momentum= Final momentum

→ 0=m1v1+m2v2

Substituting the values of m1,v2 and m2,,we get,,

0=10v1+(6×20)

→0=10v1+120

→ -120/10=v1

→v1=-12 m/s

Hence,speed of mass 10kg is 12 m/s.

Negative sign shows that the velocity of 6kg is opposite of the 10kg.

________________________________

HOPE IT HELPS ❣️❣️❣️

-----------------------------------------------------------