Question

a bomb of mass 20 kg initially at rest explodes into two pieces of mass of 10 kg m1 and m2 if the heavier one remain at rest and other move in opposite direction to each other with same speed of 10 m/s.then find the ratio of m1 to m2​

Answer 1

Hello Dear,

◆ Answer -

m1:m2 = 1:1

◆ Explanation -

Initially the bomb of mass 20 kg is at rest.

Initial momentum of the system is -

pi = M.u

pi = 20 × 0

pi = 0 kgm/s

Later bomb exploded into m1, m2 and 10 kg pieces.

Let v be magnitude of velocity of m1 and m2. So v1 = -v2 = v

Final momentum of the system is -

pf = m1.v1 + m2.v2 + m3.v3

pf = m1.v + m2.(-v) + 10×0

pf = m1.v - m2.v

According to law of conservation of momentum -

pi = pf

0 = m1.v - m2.v

m1.v = m2.v

m1/m2 = 1

Hence, ratio of m1:m2 = 1:1 .

Hope this helps you...