Question

a bomb of mass 30 kg at rest explodes into 2 pieces of 18 kg and 12 kg the velocity of 18 kg mass is 6 m/s the KE of the other mass will be ?

Answer 1

initial momentum of bomb is 0 

after exploding the speed of mass 18 kg is 6 m/s and the speed of mass 12 be U
 
so momentum after collision = momentum 1 + momentum 2
P = 18 x 6 + 12 x U
P = 108 + 12 U

now according to conservation of momentum
momentum before collision = momentum after collision
o = 108 + 12 U
-108 = 12U
-108/12 = U
-9 = U
  

so KE = 1/2 m v square
KE = 1/2 x 12 x -9 square
KE = 486 J

Answer 2

Explanation:

i hope this will help you