A bomb of mass 30 kg at rest explodes into two pieces of masses 18kg and 12 kg . the velocity of 18 kg mass is 6 m/s. the kinetic energy of the other mass is –
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the answer is 486 J because the v over here is 9.so that is the explanation of the question,
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Question:
A bomb of mass 9 kg explodes into two pieces of 3 kg and 6 kg the velocity of 3 kg pieces 16 m per second the kinetic energy of 6 kg piece is.
Answer:
When the bomb explodes into two pieces then:
Mass of one part (m1)= 3kg
Velocity of that part (v1)= 16m/s
Mass of another part (m2)= 6kg
Velocity of another part (v2)= ?
By the conservation of linear momentum;
m1 * u1 +m2 * u2 = m1 * v1 + m2 * v2
m1 * v1 + m2 * v2 = 0
m1 * v1 = -m2 * v2
So taking magnitude only:
m1 * v1 = m2 * v2
3 * 16 = 6 * v2
v2 = 8 m/s
Now, kinetic energy (KE2) = 1/2 (m2 *v2²)
=0.5 * 6 * 8²
= 3 * 64
=192 joule s
Hence the KE of of 6kg mass is 192 joules
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