Question

A bomb of mass m is thrown with velocity v. It explodes
and breaks into two fragments. One fragment of mass
m', immediately after the explosion, comes to rest.
Determine the speed of the other fragment.​

Answer 1

Explanation:

here we can conserve the momentum

so

mv = m'(0) + m-m'(v')

mv/ m-m'= v'

Answer 2

Answer:

it is also at rest

Explanation:

• according to law of conservation of mass
• M1V1= M2V2
• M1V1-M2V2 =0
• so the other piece shold go into the opposite direction so it is rest