Question

A bomber is moving with a velocity v (m/s) above H meter from the ground. The bomber releases a bomb to hit a target T when the sighting angle is θ. Then the relation between θ, H and v is -  (a) θ = tan v 2Hg -1 (b) θ = tan v 2 / gH -1 (c) θ = tan v H / 2g -1 (d) None of these​

Answer 1

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