Question

a bos contain 90 dice which are numbered 1 to 90 .if one dice is drawn at random find the probality that it brars. (1)a perfect square 2)a number divisble by5​

Answer 1

Step-by-step explanation:

1) favourable outcome = 1,4,9,16,25,36,49,64,81

= 9

total outcome = 90

p of getting a perfect square = 9/90

= 1/10

2) favourable outcome = 90/5 = 18

total outcome =90

p of getting a no which is divisible by 5 = 18 /90

= 1/5

.

hope it will help u

pl mark me as brainlist

Answer 2

Step-by-step explanation:

Total number of discs=90

1. Total number of two digit numbers between 1 and 90=81

P(getting a two digit number)=81/90=9/10

2. Perfect square between 1 and 90 are 1,4,9,16,25,36,49,64 and 81.

therefore, total number of square between 1 and 90 is 9

P(getting a perfect square)=9/90=1/10

3. Number that are between 1 and 90 and divisible by 5 are 5,10,15,20,25,30,35,40,45,50,55,60,65,70,75,80,85,90. Therefore,total numbers divisible by 5=18

Probability of getting a number divisible by 5=18/90=1/5