Question

a bottle contain 20 liters of liquid a is taken out of it and replaced by same quentity of liquid B.again 4 liters of the mixture is taken out and replaced by same que
ntity of liquid B.what is the ratio of quentity of liquid A to thatof liquid B in the final mixture​

Answer 1

Step-by-step explanation:

Let A is 5x,and B is 3x.

In removal of 16l of mixture,

A removed=(5/8)×16=10l,

B removed=(3/8)×16=6l.

Now,as per question,16l of B is added.

Hence,new content of B=3x-6+16=3x+10.

NewA:new B=3:5

(5x-10):(3x+10)=3:5

Solving,we get X=5

Hence, volume of vessel=8x=40l