Chemistry, asked by samridh3215, 11 months ago


A bottle labelled with "12 V H2O2"contain 700 mL solution. If a student mix 300 mL water in it what is the
g/litre strength & normality and volume strength of final solution.

Answers

Answered by ganumatt2003
30

Answer:

Strength = 25.2 g/L, Normality = 1.5N, V.S(final) = 8.4V

Explanation:

12V h2o2 means 1L of h2o2 gives 12L of o2 on decomposition

therefore, 700ml of h2o2 gives 700/1000 x 12 = 8.4V

Normality = V/5.6 ==> 8.4/5/6 = 1.5N

Strength = 3V(approximately) ==> 3x8.4 = 25.2 g/L

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