A bought a table for rupees 7500 and sold it to B at a loss of 19 percent .Bsold it to C at a profit of 17% how much did C pay for it?
Answers
Answered by
1
Step-by-step explanation:
₹7107.75 I think correct answers
Answered by
1
Answer:
Rs 7107.75
Step-by-step explanation:
A's Cost Price = 7500
A's Selling Price = 19% loss
= 19% of 7500
=19/100x7500=19/1x75
=19x75
= Rs 1425
Now we need to subtract Rs 1425 from Rs 7500
=7500-1425
=6075
Thus A's Selling Price is Rs 6075
B's Cost Price = Rs 6075
B's Selling Price = 17%
=17% of 6075
=17/100x6075
=6075x17/100
=103275/100
=Rs 1032.75
Now we need to add Rs 1032.75 to Rs 6075
=6075+1032.75
=Rs 7107.75
C's Cost Price = B's Selling Price
Thus C payed Rs 7107.75 for the table
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