Math, asked by sgcsuryanshi25jul5, 5 days ago

A bought a table for rupees 7500 and sold it to B at a loss of 19 percent .Bsold it to C at a profit of 17% how much did C pay for it?​

Answers

Answered by Aishwarya121234
1

Step-by-step explanation:

₹7107.75 I think correct answers

Answered by 21sv0056abhiram
1

Answer:

Rs 7107.75

Step-by-step explanation:

A's Cost Price = 7500

A's Selling Price = 19% loss

= 19% of 7500

=19/100x7500=19/1x75

=19x75

= Rs 1425

Now we need to subtract Rs 1425 from Rs 7500

=7500-1425

=6075

Thus A's Selling Price is Rs 6075

B's Cost Price = Rs 6075

B's Selling Price = 17%

=17% of 6075

=17/100x6075

=6075x17/100

=103275/100

=Rs 1032.75

Now we need to add Rs 1032.75 to Rs 6075

=6075+1032.75

=Rs 7107.75

C's Cost Price = B's Selling Price

Thus C payed Rs 7107.75 for the table

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