Physics, asked by Brianaaaaa, 11 months ago

A bowling ball (8kg) moving at 2m/s rolls into a pillow and comes to a stop in 0.5s. With what force did the bowling ball hit the pillow?

Answers

Answered by Anonymous
1

hey mate your answer

Given:

v=0 m/s( lastly object come to rest)

u= 2m/s

t=0.5 s

m= 8 kg

F=?

Solution:

  • Formula used

v=u+at

F=ma

v=u+at

0=2+0.5a

-0.5a=2

a=-2/0.5

a=-20/5

a=-4 m/ s^2

F=ma

=8×(-4)

= -32 N

The bowling ball hit the pillow with -32N force

hope it helps you!

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