A box 600 electric bulb s contains 12 defective bulbs One bulb is taken out random from this box what is probability that it is a non defective bulb?
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588/600
588/600
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1
Total number of bulbs=600
defective bulbs =12
therefore,not-defective bulbs=600-12= 588
therefore,p( getting not defective bulbs)=588/600
defective bulbs =12
therefore,not-defective bulbs=600-12= 588
therefore,p( getting not defective bulbs)=588/600
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