A box a contains 2 white, 3 red and 2 black balls. Another box b contains 4 white, 2 red and 3 black balls. If two balls are drawn at random, without replacement, from a randomly selected box and one ball turns out to be white while the other ball turns out to be red, then the probability
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Total posible outcomes = balls in box A + balls in box B = 16
No. Possible outcome = no. of red and white balls in a box B = 6
Probability that the ball is drawn from box B = no. of posaible outcomes/ total no. of posaible outcomes =
6/16 = 3/8
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Answer:
For white ball
P(A) = 6/16
For red ball.
P(A) = 5/16
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