Question

A box at the top has its outer dimension 10 cm and 9 cm and 2.5 cm and its thickness is 0.5 cm find the volume of the metal

Answer 1

Answer : -

Given that,

Length = 10 cm

Breadth = 9 cm

Height = 2.5 cm

Thickness = 0.5 cm

First of all, we've to find the volume of the cuboidal box regardless it's thickness.

Volume regardless thickness,

Volume of cuboidal box = lbh

Volume of cuboidal box = $10\:cm \times 9\:cm \times 2.5\:cm$

Volume of cuboidal box = 225 cm³

Now, we'll subtract the thickness from the volume so that, we'll get an exact value of the volume of the cuboidal box.

Exact volume,

Exact volume = volume regardless thickness - thickness of the cuboidal box.

Exact volume = 225 - 0.5

Exact volume = 224.5 cm³

Therefore, the exact volume of the cuboidal box is 224.5 cm³.

$\huge{\boxed{\pink{Volume = 224.5\:cm^3}}}$

Answer 2

Answer:

Volume of the metal = 81 cm^3.

Step-by-step explanation:

Given: Length = 10 cm.

• Breadth = 9 cm.
• Width = 2.5 cm.

We know that Volume of the outer metal= l * b * h

=> 10 * 9 * 2.5

=> 225 cm^3.

Given that thickness is 0.5 cm.

=> Length = 10 - (0.5 + 0.5)

                = 9 cm.

=> Breadth = 9 - (0.5 + 0.5)

                  = 8 cm.

=>  Width = 2.5 - (0.5)

               =  2 cm.

So, volume of the inner metal = l * b * h

=> 9 * 8 * 2

=> 144 cm^3.

Now,

Volume of the metal = 225 - 144

=> 81.

Therefore, Volume of the metal = 81 cm^3.