Question

A bodystart withan intiaio velocity of 10 m s1 and acceleration 5 m s-2 find the distance covered by it in 5 s.

Answer 1

Question : -

A body starts with an initial velocity of 10 m/s and acceleration of 5 m/s². Find the distance covered by it in 5 s.

Answer : -

Given that,

Intial velocity (u) = 0 m/s

Final velocity (v) = 10 m/s

Acceleration = 5 m/s^2

Time = 5 s.

By using second equation of motion,

s = ut + $\frac{1}{2}$ at²

s = $0 \times 5 \times \frac{1}{2} \times 5 \times 5 \times 5$

s = $0 + \frac{1}{2} \times 125$

s = $\frac{125}{2}$

s = 62.5 m

So, the body will cover 62.5 m.

$\huge{ \boxed{ \pink{distance = 62.5m}}}$