Question

A BOX CONTAIN 3 BLUE BALLS,2 WHITE BALLS,2 BLACK BALLS AND 5 RED BALLS. IF A BALL IS DRAWN AT RANDOM FROM FROM THE BOX. WHAT WILL BE THE PROBABILITY THAT IT WILL BE (a)WHITE (b)RED (c)BLACK (d)BLUE

Answer 1

Total ball =3+2+2+5 = 12//

Blue Ball =3,

White Ball=2,

Black Ball =2,

Red Ball=5.

(a) White=(2/12)//

(b) Red = (5/12)//

(c) Black=(2/12)//

(d) Blue=(3/12)=//

Answer 2

The box contain total (3+2+2+5)=12 balls.One ball can be drawn from 12 balls in 12C1=12 way.
a) 1 ball can be drawn from 2 white balls in 2C1=2 ways.
Probability of the event that the drawn ball is white : P(A)=2/12=1/6
b)1ball can be drawn from 5 red balls in 5C1=5 ways. Probability of the event that the drawn ball is red : P(B)=5/12
c) 1ball can be drawn from 2 black balls in 2C1=2 ways. Probability of the event that the drawn ball is black : P(C)=2/12=1/6
d) 1ball can be drawn from 3 blue balls in 3C1=3 ways. Probability of the event that the drawn ball is blue : P(D)=3/1=1/4